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What exactly is +EV and -EV, spawgan, 8. Sep 2003 17:42
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I know I probably have just not come across it in my reading thus far, but I see the terms +EV and -EV in several posts. While I can from the context get a good idea what the terms mean, could someone give me a more precise definition so I can take more away from these posts I am reading referring to those plays.

Thank you in advance.
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Re: What exactly is +EV and -EV, Big Frank, 8. Sep 2003 18:11
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+EV and -EV means positive or negative expected value. Essentially, these terms are most often used to explain the statistical probability of a call, bet or raise either making money or losing money given the complete set of circumstances (hand, previous action, position etc)
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Re: What exactly is +EV and -EV, Bart Mann, 8. Sep 2003 18:21
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EV or +EV stands for "Expected Value" or "Positive Expected Value." An easy illustration is this: if you place $2 on a bet that's a 50/50 shot, the "Expected Value" of the proposition is exactly $1 (.5 x $2 = $1). -EV stands for "Negative Expected Value." You reach negative expected value when the "Expected Value" or outcome of the proposition you are considering is below $0. Here's an easy example of "Negative Expected Value":

Let's say that there's a 75% chance of losing $1, but a 25% chance of winning $1. The "Expected Value" of this proposition is a loss of 50 cents, as follows:

(.75 x -$1) + (.25 x +$1) = -$.75 + $.25 = - $.50

Make sense?
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AM I GOOFED up?, WilliamS, 9. Sep 2003 07:02
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on 8. Sep 2003 18:21 Bart Mann wrote:
> EV or +EV stands for "Expected Value" or "Positive Expected Value." An easy
> illustration is this: if you place $2 on a bet that's a 50/50 shot, the "Expected
> Value" of the proposition is exactly $1 (.5 x $2 = $1).

My question is how does this have a positive EV? Shouldn't it be zero, neither positive or negative since it is an even money bet?

Will

-
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Re: AM I GOOFED up?, Bart Mann, 9. Sep 2003 07:30
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I see what you mean--I blew that one. That part should read:

"If you place a bet that has a 50% chance of paying $2 and a 50% chance of paying $0, the Expected Value of the bet is $1 (.5 x 2 + .5 x 0)"

Must have been sleepy yesterday. Nice catch.
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Re: AM I GOOFED up?, stdioh, 12. Sep 2003 09:10
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No, the expected value of that bet is still $0. If you were to bet $2 and either win $4 or win $0 then your expected value is +$1.

.5*-2 + .5*+4 = -1+2=1
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Re: What exactly is +EV and -EV, stdioh, 9. Sep 2003 11:11
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The simple answer:
+EV the amount you expect to earn from every dollar you bet, in the long run.
- EV the amount you expect to lose.

For instance, if you flip a coin, your EV is zero. Half the time you win and half the time you lose. Flipping billions of coins you expect to average no gain or loss.
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