|
||
|
||
|
Server Time: 11/21/2008 11:54:11 PM PACIFIC |
 Rake prob !, mandeep, 19. Jul 2003 07:05 | ||
| View ( Message | Thread ) | Return to Thread List | |
| RAKE PROBLEM Consider following chart to compute rake value in a game No Limit Games No. of players Starting at $5 pot and at each $5 increment Max. 2-3 $0.25 $1 4-5 $0.25 $2 6 + $0.25 $3 Case 1: There are two players on the table and total bet accumulates to 22$ at the end of the game. This is how i tried to compute the rake Total multiples of $5 in 22$ is 4 then multiplied 4 with .25 gives me 1.00$ as the chargeable rake amout. Case 2: If There are two players on the table and total bet accumulates to 26$ at the end of the game. This is how i tried to compute the rake Total multiples of $5 in 26$ is 5 then multiplied 5 with .25 gives me 1.25$ but since for 2-3 players maximum rake allowed is 1$ so .25$ would be waived off.. Please correct if i am wrong somewhere Thanks in anticipation.. | ||
| Return to Thread List | ||
| Re: Rake prob !, Roy Cooke, 19. Jul 2003 07:46 | ||
| View ( Message | Thread ) | Return to Thread List | |
| Hello You have the rake stated as the total bet.....A bet that is NOT called should NOT constitute part of the sum of the pot as far as the rake is concerned. On the second pot the rake should never exceed $1 assuming the rake structure you quoted is correct. Roy Cooke on 19. Jul 2003 07:05 mandeep wrote: > RAKE PROBLEM > > Consider following chart to compute rake value in a game > > No Limit Games > No. of players Starting at $5 pot and at each $5 increment Max. > 2-3 $0.25 $1 > 4-5 $0.25 $2 > 6 + $0.25 $3 > > Case 1: > There are two players on the table and total bet accumulates to 22$ at the end > of the game. > > This is how i tried to compute the rake > Total multiples of $5 in 22$ is 4 > then multiplied 4 with .25 gives me 1.00$ as the chargeable rake amout. > > Case 2: > If There are two players on the table and total bet accumulates to 26$ at the > end of the game. > > This is how i tried to compute the rake > Total multiples of $5 in 26$ is 5 > then multiplied 5 with .25 gives me 1.25$ > but since for 2-3 players maximum rake allowed is 1$ so .25$ would be waived > off.. > > Please correct if i am wrong somewhere > > Thanks in anticipation.. > > | ||
| Return to Thread List | ||
| Re: Rake prob !, stdioh, 21. Jul 2003 14:38 | ||
| View ( Message | Thread ) | Return to Thread List | |
| It sounds to me like you are trying to write your own poker software. If you are indeed doing this, you might want to talk to the experts in the games group at the University of Alberta. | ||
| Return to Thread List | ||
| POKER FORUM HOME | POKER FORUM | LINK TO US | ARCHIVE | ONLINE POKER | Copyright 2002, United Poker Forum |
|
Getting Started |
UPF Tournaments |
Poker News, Views, Rules |
Poker Strategy & Psychology |
Money and Bankroll Poker Bonuses & Promotions | World Series of Poker (WSOP) | Play Online Poker | Poker Odds & Statistics | Tournament Poker | Poker Books, Videos & Learning Tools Looking for a Poker Game | Poker Bad Beats | Not Quite Poker | Quizzes and Polls | Forum Suggestions & Bugs |
|
|
|
|
Interesting Links: Online Poker | Free Poker Games | United Poker Network |
|