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Server Time: 12/3/2008 8:53:26 PM PACIFIC |
 Hold em", William Schipani, 30. Sep 2002 13:04 | ||
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| > Question #1 On a 10 handed hold'em game what are the odds or chances of one player having pocket aces and another player having pocket kings? > > Question #2 On a 10 handed hold'em gane, what are the odds or chances of two players having pocket pairs both flopping sets? Can anyone answer these questions? Please!!! > | ||
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| Re: Hold em", Mano, 30. Sep 2002 14:32 | ||
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| > > Question #2 On a 10 handed hold'em gane, what are the odds or chances of two > players having pocket pairs both flopping sets? > Given that we know the 2 players have different pocket pairs, there are 48 cards left. There are 2 of each pair's rank remaining which must be chosen and the remaining card can be chosen from among the other 46 cards, so there are 2*2*46 = 184 ways of flopping the 2 sets out of a total of C(48,3) = 17296 different flop possibilities. Dividing the first number by the second number gives us a probability of about 1.06 % and an odds of 93:1 against both players flopping a set (again, given that the 2 players have a pair to start with). | ||
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| Re: Hold em", Roy Cooke, 30. Sep 2002 19:59 | ||
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| on 30. Sep 2002 13:04 William Schipani wrote: > > Question #1 On a 10 handed hold'em game what are the odds or chances of one > player having pocket aces and another player having pocket kings? Around 540-1 > > > > Question #2 On a 10 handed hold'em gane, what are the odds or chances of two > players having pocket pairs both flopping sets? Assuming they both have a pair.....Around 90-1 > > Can anyone answer these questions? Please!!! I am not an expert in math...but those are pretty close. Roy Cooke > > > | ||
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| Re: Hold em", RickyK, 15. Oct 2002 06:31 | ||
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| > > Question #2 On a 10 handed hold'em gane, what are the odds or chances of two > players having pocket pairs both flopping sets? >Assuming they both have a pair.....Around 90-1 > > Can anyone answer these questions? Please!!! >I am not an expert in math...but those are pretty close. I think 93-1 is correct, for what it's worth. | ||
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